How this calculator works
A rectangular cage volume is divided by a stated volume allowance and rounded down to a whole number. Two common planning allowances are offered transparently, without claiming they are research-backed stocking standards. The cited expert-consultation paper emphasizes multiple housing features and substantial floor dimensions. An empty geometric volume overstates usable space when fixtures occupy much of the cage.
Formula
Volume = length × width × height. Arithmetic count = floor(volume / chosen allowance). Missing dimension = known volume / product of the other two dimensions. One cubic foot = 0.028316846592 m3.
Worked example
A 1 m by 0.6 m by 1.2 m cage has 0.72 m3 of geometric volume. Under a custom 0.1 m3 allowance, the arithmetic count is seven. A 0.5 m3 cage under the same assumption gives five. Neither result approves a housing arrangement.
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Frequently asked questions
Can a narrow tall cage pass based on volume?
It can have a high arithmetic count while offering poor floor space. This calculator does not certify a cage as suitable.
Are the two preset allowances legal or welfare standards?
No. They are explicitly labelled planning assumptions. Seek current species-specific welfare guidance for a real enclosure.
Can I solve a missing dimension?
Yes. Enter known volume and the other two dimensions. The result reconstructs the rectangle without assessing the layout.