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Combined gas law calculator

Solve a combined gas-law state variable or model an isothermal, isobaric, isochoric or reversible adiabatic ideal-gas process with heat and work.

Calculator

Final absolute pressure
50,000
Final volume
0.02
Final temperature
300
Inferred amount of gas
0.400908
Molar heat capacity Cv (J/(mol K))
20.78615655
Internal energy change
0
Work done by gas
693.147
Heat added to gas
693.147

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How this calculator works

The combined gas law compares two equilibrium states of a fixed amount of ideal gas using absolute pressure and temperature. Process mode also imposes a path constraint and computes work done by the gas, internal energy change and heat added. The initial state determines amount of gas. Heat capacities are assumed constant, with Cv inferred from a supplied ratio Cp/Cv. Adiabatic mode is reversible and quasi-static.

Formula

p1 V1/T1 = p2 V2/T2; n = p1 V1/(R T1); deltaU = n Cv (T2 - T1); Q = deltaU + W_by. Isothermal W = nRT ln(V2/V1); reversible adiabatic pV^gamma is constant.

Worked example

Isothermal expansion from 100 kPa and 0.01 m³ to 0.02 m³ gives 50 kPa and 693.147 J of work. At fixed volume, increasing 300 K to 600 K doubles pressure; with gamma = 1.4 the same initial state gains 2500 J of internal energy.

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Frequently asked questions

Can I enter gauge pressure?

Convert it to absolute pressure first by adding the relevant ambient pressure.

Why is the final-temperature field unused for some processes?

In process mode it applies to isochoric changes. The other processes use final volume and infer final temperature from their path constraint.

Is positive work compression?

Positive work is work done by the gas during expansion. Compression gives negative work under this sign convention.

Sources

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