Advertisement

Inverse square law calculator

Estimate how intensity changes with distance from a compact source emitting into an unchanged solid angle.

Calculator

Final intensity (entered units)
25.00000000
Relative intensity with distance Line chart. The data table follows. 0 0 1.25 1 2.5 2 3.75 3 5 4 Distance / initial distance Intensity / initial intensity
Relative intensity with distance data
SeriesDistance / initial distanceIntensity / initial intensity
Point source0.54
Point source0.556253.2319151622269913
Point source0.61252.665556018325697
Point source0.668752.2360031443794224
Point source0.7251.9024970273483948
Point source0.781251.6384
Point source0.83751.4257072844731566
Point source0.893751.2518949581886645
Point source0.951.10803324099723
Point source1.006250.9876162185100882
Point source1.06250.8858131487889274
Point source1.118750.7989763116007617
Point source1.1750.7243096423721139
Point source1.231250.6596408049679199
Point source1.28750.6032613818456027
Point source1.343750.5538128718226069
Point source1.40.5102040816326532
Point source1.456250.4715504061596272
Point source1.51250.43712861143364523
Point source1.568750.40634275646418305
Point source1.6250.378698224852071
Point source1.681250.353781733254101
Point source1.73750.3312457947311216
Point source1.793750.31079653753232406
Point source1.850.2921840759678597
Point source1.906250.27519484009674816
Point source1.96250.25964542172096233
Point source2.018750.2453776035426392
Point source2.0750.23225431847873415
Point source2.131250.22015634540466625
Point source2.18750.2089795918367347
Point source2.243750.19863284735531228
Point source2.30.18903591682419663
Point source2.356250.18011806176079476
Point source2.41250.17181669306558564
Point source2.468750.1640762698285531
Point source2.5250.15684736790510737
Point source2.581250.15008588899506947
Point source2.63750.14375238651422922
Point source2.693750.13781148895623946
Point source2.750.1322314049586777
Point source2.806250.12698349710566914
Point source2.86250.12204191376976031
Point source2.918750.11738327013283566
Point source2.9750.11298637101899582
Point source3.031250.10883196939100862
Point source3.08750.1049025553606845
Point source3.143750.10118217138520766
Point source3.20.09765624999999999
Point source3.256250.09431147100106468
Point source3.31250.09113563545745818
Point source3.368750.08811755432481645
Point source3.4250.085246949757579
Point source3.481250.08251436749191778
Point source3.53750.079911098902471
Point source3.593750.07742911153119092
Point source3.650.07506098705197974
Point source3.706250.07279986577524748
Point source3.76250.07063939691614882
Point source3.818750.06857369395238949
Point source3.8750.06659729448491156
Point source3.931250.06470512408976825
Point source3.98750.06289246371399652
Point source4.043750.061154920223884336
Point source4.10.0594883997620464
Point source4.156250.05788908361128385
Point source4.21250.056353406299254186
Point source4.268750.05487803570930934
Point source4.3250.053459854990143336
Point source4.381250.052095946080695815
Point source4.43750.05078357468756199
Point source4.493750.049520176570379576
Point source4.550.04830334500664172
Point source4.606250.04713081932142666
Point source4.66250.04600047437989205
Point source4.718750.04491031095127407
Point source4.7750.043858446862750464
Point source4.831250.04284310887002974
Point source4.88750.041862625179060836
Point source4.943750.0409154185599371
Point source50.04

Advertisement

How this calculator works

As radiation spreads over a growing spherical surface, the same flux is shared over area proportional to distance squared. The relation applies to an ideal compact source in a uniform non-absorbing medium. Both intensities must use the same units and both distances must start at the source. Extended sources and focused beams may behave differently.

Formula

I1 r1² = I2 r2²; I2 = I1(r1/r2)²; r2 = r1 sqrt(I1/I2).

Worked example

An intensity of 100 units at 2 m becomes 25 units at 4 m. At 1 m it would be 400 units under the same point-source assumptions.

Advertisement

Frequently asked questions

Does doubling distance halve intensity?

It reduces intensity to one quarter because the illuminated area grows fourfold.

Does it apply inside an absorbing material?

Absorption adds a separate transmission factor, so the pure inverse-square relation is incomplete.

Can I use any intensity units?

Yes, provided both entries use the same physical quantity and the same units.

Sources

Advertisement