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Magnetic moment calculator

Use orbital, spin and total angular momentum to calculate an LS-coupled atomic effective moment in Bohr magnetons.

Calculator

Spin quantum number S
0.50000000
Orbital quantum number L
0.00000000
Total quantum number J
0.50000000
Lande g factor
2.00000000
Effective moment (Bohr magnetons)
1.73205081
Effective moment (J/T)
0.00000000
Moment convention
Effective magnitude |g| sqrt[J(J+1)] muB; not the saturated projection |g|J muB.
Scientific notation for small or large results
QuantityValue in the stated units (SI for dimensioned outputs)
Effective moment (J/T)1.6063056646e-23

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How this calculator works

The LS-coupling approximation adds total orbital L and spin S to form J. Using orbital gL = 1 and spin gS = 2 gives the usual Lande factor. The reported effective magnitude is |gJ| sqrt[J(J+1)] Bohr magnetons, the quantity commonly used in Curie-law estimates. It differs from the maximum field projection |gJ|J. The moment-only inverse chooses a nonnegative g because magnitude cannot determine its sign. Nuclear moments, anomalous electron spin corrections and strong spin-orbit or crystal-field effects are omitted. J = 0 has zero first-order moment but no defined g factor.

Formula

gJ = 1 + [J(J+1)+S(S+1)-L(L+1)]/[2J(J+1)]; mu_eff/muB = |gJ| sqrt[J(J+1)]. J ranges in integer steps from |L-S| to L+S.

Worked example

For L = 0, S = J = 1/2, g = 2 and the effective moment is sqrt(3), about 1.73205 Bohr magnetons. For S = 0 and L = J = 1 it is sqrt(2) Bohr magnetons.

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Frequently asked questions

Is the effective moment the maximum projection?

No. The magnitude uses sqrt[J(J+1)], while the saturated projection uses J.

Why do some inverses fail?

Not every g and angular-momentum combination describes an allowed multiplet, and some inverse equations are underdetermined.

What happens at J = 0?

The first-order effective moment is zero. Dividing to define g at J = 0 is not meaningful.

Sources

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